Inverse matrix . Said of squareMatrix A -1 of order N that given a nonsingular A square matrix of the same order, satisfies AA -1 = A -1 A = I N .
Summary
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- 1
- 2
- 3 Methods of obtaining inverse matrices
- 4 Solution of systems of linear equations using the inverse
- 5
- 1 Solving a system of linear equations
- 6 See also
- 7 Sources
Definitions.
Given the square matrix A of order N it is said to be an invertible matrix if and only if the determinant of A is not null.
If A is an invertible matrix, it is said that the square matrix A -1 of order N is the inverse matrix A such that AA -1 = A -1 A = I N .
Properties.
Relating to invertibility:
- A square matrix Ais invertible if there is another square matrix B such that AB = BA = I.
- An array is invertible ssi:
- It’s squared.
- It is non-singular.
- If a matrix Aof order n is invertible, then its range is also n .
- The inverse matrix if it exists is unique.
- (AB) -1= A -1 B -1
- (A T) -1 = (A -1 ) T
- (A -1) -1 = A
- I -1= I
Methods of obtaining inverse matrices
Using the determinant and the attached matrix:
- Let A + bethe attached matrix of A , A -1 = A + / | A | .
For the specific cases of invertible matrices of order 2 and 3, their inverses can be calculated in the following ways:
- Order 2:
- ,
- Whose determinate is | A | = ad-bc,
- ,
- ,
- Order 3:
- ,
- Its determinant
- The algebraic complements of each cell are calculated, obtaining the transposition of the attached matrix ,
- It transposes: ,
Gauss-Jordan Elimination Method :
- From, the extended matrix (A | I) is createdand through elementary transformations in each row, if A is invertible, it is obtained (I | A -1 ) .
Solution of systems of linear equations using the inverse
Let the matrix A be non-singular and the system of linear equations represented in the matrix equation:
- AX = B
It can be multiplied in front of both sides of the equation by A -1 :
- A -1AX = A -1 B => IX = A -1 B
from where:
- X = A -1B
which shows another way to determine the solution of a compatible linear equation system.
Examples.
Matrix:
one | 2 | 3 |
4 | 5 | 6 |
7 | 8 | 9 |
it has no inverse because its determinant is 0, that is, it is a singular matrix.
Instead matrix A :
one | 2 | 3 |
3 | 4 | 5 |
5 | 6 | 8 |
complies with | A | = -2 , is non-singular and therefore is invertible. A -1 is:
-one | -one | one |
-0.5 | 3.5 | -2 |
one | -2 | one |
Which can be obtained through the attached matrix and its determinant:
Or by the Jordan method:
- Write the augmented matrix (A | I): .
- Pivot A 1.
- .
- Replace Row2 with Row2 – 3 Row1.
- Replace Row3 with Row3 – 5 Row1.
- Pivot A 2.
- .
- Replace Row1 with Row1 + Row2.
- Replace Row3 with Row3 – 2 Row2.
- Pivot A 3.
- .
- Replace Row1 with Row1 + Row3.
- Substitute Row2 for Row2 + 4 Row3.
- Row 2 is divided by -2 and finally (I | A -1) is obtained :
- .
Linear equation system resolution
Let be the system of linear equations represented by the matrix equation AX = B :
But the matrix representing the SEL coefficients has the inverse:
And in this case the system can be restated as X = A -1 B , solving by means of the matrix product: