Inverse matrix

Inverse matrix . Said of squareMatrix A -1 of order N that given a nonsingular A square matrix of the same order, satisfies AA -1 = A -1 A = I N .

Summary

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  • 1
  • 2
  • 3 Methods of obtaining inverse matrices
  • 4 Solution of systems of linear equations using the inverse
  • 5
    • 1 Solving a system of linear equations
  • 6 See also
  • 7 Sources

Definitions.

Given the square matrix A of order N it is said to be an invertible matrix if and only if the determinant of A is not null.

If A is an invertible matrix, it is said that the square matrix -1 of order N is the inverse matrix A such that AA -1 = A -1 A = I N .

Properties.

Relating to invertibility:

  • A square matrix Ais invertible if there is another square matrix B such that AB = BA = I.
  • An array is invertible ssi:
    • It’s squared.
    • It is non-singular.
  • If a matrix Aof order n is invertible, then its range is also n .
  • The inverse matrix if it exists is unique.
  • (AB) -1= A -1 B -1
  • (A T-1 = (A -1 ) T
  • (A -1-1 = A
  • -1= I

Methods of obtaining inverse matrices

Using the determinant and the attached matrix:

  • Let + bethe attached matrix of A , -1 = A + / | A | .

For the specific cases of invertible matrices of order 2 and 3, their inverses can be calculated in the following ways:

  • Order 2:
    • ,
    • Whose determinate is | A | = ad-bc,
    • ,
    • ,
  • Order 3:
    • ,
    • Its determinant
    • The algebraic complements of each cell are calculated, obtaining the transposition of the attached matrix ,
    • It transposes: ,

Gauss-Jordan Elimination Method :

  • From, the extended matrix (A | I) is createdand through elementary transformations in each row, if A is invertible, it is obtained (I | A -1 ) .

Solution of systems of linear equations using the inverse

Let the matrix A be non-singular and the system of linear equations represented in the matrix equation:

  • AX = B

It can be multiplied in front of both sides of the equation by -1 :

  • -1AX = A -1 B => IX = A -1 B

from where:

  • X = A -1B

which shows another way to determine the solution of a compatible linear equation system.

Examples.

Matrix:

one 2 3
4 5 6
7 8 9

it has no inverse because its determinant is 0, that is, it is a singular matrix.

Instead matrix A :

one 2 3
3 4 5
5 6 8

complies with | A | = -2 , is non-singular and therefore is invertible. -1 is:

-one -one one
-0.5 3.5 -2
one -2 one

Which can be obtained through the attached matrix and its determinant:

Or by the Jordan method:

  • Write the augmented matrix (A | I): .
  • Pivot A 1.
    • .
    • Replace Row2 with Row2 – 3 Row1.
    • Replace Row3 with Row3 – 5 Row1.
  • Pivot A 2.
    • .
    • Replace Row1 with Row1 + Row2.
    • Replace Row3 with Row3 – 2 Row2.
  • Pivot A 3.
    • .
    • Replace Row1 with Row1 + Row3.
    • Substitute Row2 for Row2 + 4 Row3.
  • Row 2 is divided by -2 and finally (I | A -1) is obtained :
    • .

Linear equation system resolution

Let be the system of linear equations represented by the matrix equation AX = B :

But the matrix representing the SEL coefficients has the inverse:

And in this case the system can be restated as X = A -1 B , solving by means of the matrix product:

 

by Abdullah Sam
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